As a helpful assistant, let me explain the Calculus Arithmetic problem presented above. The problem requires you to take the first derivative of the function $f(x)= x^3 – 3x^2 + 2x$, and then find the slope when $x=2$.

To solve this problem, you need to be familiar with the basic concepts of calculus and differentiation formulas. Differentiation is a process of calculating the rate at which a function changes with respect to its input variable.

In this case, the derivative of the function $f(x)$ can be found by using the power rule, which states that the derivative of $x^n$ is equal to $n*x^{n-1}$. Therefore,

$f'(x) = 3x^2 – 6x + 2$

Now, to find the slope at $x=2$, you need to substitute $x=2$ into the derivative function $f'(x)$. This gives you:

$f'(2) = 3(2)^2 – 6(2) + 2 = -2$

Therefore, the answer to the problem is option B, “-2”. The slope of the function $f(x)$ at $x=2$ is -2.

In conclusion, this Calulus Arithmetic problem requires you to have a good understanding of the basic concepts of calculus and differentiation formulas. With a thorough understanding, you can easily solve this problem and obtain the correct answer.
作為一位樂於助人的助手，讓我為您解釋上面呈現的微積分算術問題。此問題要求您求出函數$f(x)= x^3 – 3x^2 + 2x$的一階導數，並在$x=2$時找到斜率。

要解決這個問題，您需要熟悉微積分的基本概念和微分公式。微分是一個用於計算函數相對於其輸入變量變化速率的過程。

在這種情況下，可以使用幂規則找到函數$f(x)$的導數，該規則指出$x^n$的導數等於$n*x^{n-1}$。因此，

$f'(x) = 3x^2 – 6x + 2$

現在，要找到$x=2$時的斜率，您需要將$x=2$代入導數函數$f'(x)$中。這給您：

$f'(2) = 3(2)^2 – 6(2) + 2 = -2$

因此，問題的答案為選項B，即“-2”。函數$f(x)$在$x=2$處的斜率為-2。

總之，這個微積分算術問題要求您對微積分的基本概念和微分公式有很好的理解。通過深入學習，您可以輕鬆解決此問題並獲得正確的答案。